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4u^2-2u+1=7u^2+3u+5
We move all terms to the left:
4u^2-2u+1-(7u^2+3u+5)=0
We get rid of parentheses
4u^2-7u^2-2u-3u-5+1=0
We add all the numbers together, and all the variables
-3u^2-5u-4=0
a = -3; b = -5; c = -4;
Δ = b2-4ac
Δ = -52-4·(-3)·(-4)
Δ = -23
Delta is less than zero, so there is no solution for the equation
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